-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On 15-07-12 17:40, Harry Spier wrote: > 1) In section 8 of the Racket reference there is this example: > ------------------------------------------- Examples: > (define-struct tree (val left right)) > >> (match (make-tree 0 (make-tree 1 #f #f) #f) > [(tree a (tree b _ _) _) (list a b)]) > > '(0 1) ---------------------------------- > > but I wasn't able to find any reference in the documentation to a > constructor form make-struct-id . I'm assuming that in the above > example (match (make-tree 0 (make-tree 1 #f #f) #f) is equivalent > to (match (tree 0 (tree 1 #f #f) #f) > > Is that correct? Is make-struct-id a deprecated form of the > constructor procedure struct-id?
I believe define-struct is the deprecated struct-defining form creating a "make-"-prefixed constructor and the new way is `struct' which creates constructors with the name of the struct. Marijn -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.19 (GNU/Linux) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAlAEBSEACgkQp/VmCx0OL2wfqQCfUaFVPm0Ci3wtmIX4MUY+fb60 7x0AnRPQNz3Yz6r1RPL3w8FqQg3QC/k8 =fEMY -----END PGP SIGNATURE----- ____________________ Racket Users list: http://lists.racket-lang.org/users
