The format of prob11's data is already quite close to what the reader expects for a vector, so you can read it directly by including #( ...
(define tbl
#(08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
<snip> ...
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48))
A convenience function to read the table is then:
(define (get i j)
(vector-ref tbl (+ (* i 20) j)))
Here is my across function, I use a for/fold loop. The vertical and diagonal
cases are similar.
(define (across)
(for*/fold ([mx 0])
([i (in-range 0 20)]
[j (in-range 0 17)])
(max mx (* (get i j)
(get i (+ j 1))
(get i (+ j 2))
(get i (+ j 3))))))
Does that help?
- Tom
On 2012-03-24, at 11:01 PM, Joe Gilray wrote:
> I was playing around with ProjectEuler #11 and found a lisp solution and
> adapted it to Racket. Part of the solution had code like the following to
> find products of values in a 20x20 vector.
>
> (define (prod-of-vec-lines-of-length-4 v ix iy dx dy)
> (do ([p 1 (* p (if (in-vector? x y 20 20) (vector-ref v (+ (* 20 y) x))
> 0))]
> [x ix (+ x dx)]
> [y iy (+ y dy)]
> [c 0 (add1 c)])
> ((= c 4) p)))
>
> I realize I've hard-coded this in a very ugly fashion to 20x20 vectors.
>
> My questions are:
>
> 1) Is there a more Racket-idiomatic way to write the "do" loop above?
> 2) If I wanted to use srfi/25 to do this in a nicer fashion, how would I read
> in the array? - I liked being able to read in the vector with simply (read
> in) - is there a simply , one-line way to convert a vector to an array
> (make-array (shape 0 20 0 20) vec) puts the entire 400 element vector into
> the first element of the array!
>
> Thanks,
> -joe
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