I'd like to be able to write something like this:
(let loop ([a 1] [b 2])
(if (= a b)
3
(loop (values (add1 a) b))))
This would match the way for/fold works with more than one value.
However, I get a message, "context expected 1 value, received 2
values: 2 2", which makes sense given the expansion of named let, but
it would be nice if this worked. Using (call-with-values (lambda ()
(values (add1 a) b)) loop) works, but that seems to defeat the point
of using a named-let form for clarity. I could also use let-values to
deconstruct the values and pass them individually to the loop, but
that hardly seems better. Is there a better way?
Justin
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