Hi to all schemers,
I know that "eval" evaluates the argument without
visibility of the local environment where it is called.
so the following code has this error:
> (let ((x 1)) (eval '(+ x 1))
reference to undefined identifier: x
On contrary, if "x" is defined in the top environment, I have:
> (define x 2)
> (let ((x 1)) (eval '(+ x 1))
4
So the eval sees the global environment.
Can someone tell me if it possible to evaluate a
quoted expression in such a way all local bindings
(the "let" bindings" are visible to the eval?
In my case I need to eval a quoted lambda which uses
variables that "should" bound in the local environment ...
this is the code:
> (let ((x 1)
(f (eval '(lambda (y) (+ x y)))))
(f 2))
reference to undefined identifier: x
PS. my lambda is generated by a macro (define-syntax) ...
this is why I use eval to generate the corresponding procedure.
TIA,
Maurizio Giordano
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