5 hours ago, Richard Lawrence wrote:
>
> > Both regexps use [^\S\n] to match non-newline whitespace.
>
> It's handy to know that "\\\n" is the right way to represent a
> newline literal in a regexp. That wasn't obvious from the
> documentation.
It's not the way to represent literal newlines. Newlines have no
special meaning in regexps, so you represent them as you would
represent newlines in a string -- with just #rx"\n" (or #px"\n" etc).
It just happens to work as #rx"\\\n" too, because if the literal that
follows a backslash is not a special one, then it matches the literal
itself.
--
((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://barzilay.org/ Maze is Life!
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