I have been trying to take a break for the weekend and I am going to try to go
back at it with a fresh perspective Monday.
One
thought I did have though, you said tabulate-div means we want all the
divisors of 20, so the next step would be tab-div(sub1 n), or 19, Im
thinking that would mean all the divisors of 19. But I cant think how
that is relevant.
Just so I understand, my idea of what exactly
generative recursion is that it takes some input data, applies it to a
helper function, changes the value to the answer of the helper function
and restarts the generative function. Is this a correct understanding?
so
if the helper function was (/ n 2) and the original n was 20, it would
apply 20 to / n 2, and then restart the whole function with 10 as the
new n.
I know you said to forget the whole idea of gr, but I
still think about it a lot.
the method you gave, would there still be a trivially solvable problem?
I know I will get it eventually, but this problem seems pretty
challenging, maybe I am over-complicating it. One final question I have,
would reading ahead in the book to see more of there examples help me
out?
edit, to find the solution of the first problem I had the idea of 20/20, or
n/n, my problem is wouldn't this just lead to (list 1 1 1 1 1)? since everytime
it passes the generative step, in my understanding, it does the entire function
again with all occoruences of n replaced with (helper n)
An example I hope can clarify my question is, say I have the final clause be
[else(list(/ n n)
(tabulate-div(next-divisor n(sub1 n))))]))
And next divisor does what it implies, next-divisor of 20 19 would find that it
goes until 10.
It would then take 10 and re-do the function.
So, it would check if n=10 is trivially solvable, then go to the next step,
doing list /10 10. then do next divisor of 10 9, leading to 5.
I've read through wooks post a few times and I have been trying it but I will
ultimately be spending a lot more time on it Monday, this are just some
concerns I have right now.
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