On Wed, Oct 20, 2010 at 7:20 PM, Danny Yoo <d...@cs.wpi.edu> wrote: > I'm trying to compare two paths for equality; I misread normalize-path > and didn't realize that it does not do case folding, so that on > Windows, > > (equal? (build-path "C:\\") > (build-path "c:\\")) > > returns false. What's the right way to compare paths for equality? > > As a related question, what's the right way to see if one directory is > a subdirectory of another?
Both of these operations are properly the domain of the operating system, not Scheme/Racket. There should be OS primitives or conventions for comparing equality and checking subdirectory. If these aren't provided by the system, you'll have to conditionalize your own code. -- ~jrm _________________________________________________ For list-related administrative tasks: http://lists.racket-lang.org/listinfo/users
