Hi Jonathan,
Following Gabor Grothendieck's advice, try also:
mm <- matrix(1:6, 3, dimnames = list(LETTERS[1:3], letters[1:2]))
as.data.frame.table(mm)
HTH,
Jorge
On Mon, Jun 7, 2010 at 10:33 PM, Jonathan Greenberg <> wrote:
> I have a matrix of, say, M and N dimensions:
>
> my_matrix=matrix(c(1:60),nrow=6,ncol=10)
>
> I have two "id" vectors corresponding to the rows and columns, e.g.:
>
> id_m=seq(10,60,by=10)
> id_n=seq(100,1000,by=100)
>
> I would like to create a "proper" database (let's say a data.frame for
> this example -- i'm going to be loading these into an SQLite database,
> but we'll leave that complication out of this discussion for now) of m
> x n rows, and 3 columns, where the 3 columns relate to the values from
> m, n, and my_matrix respectively, e.g. a single row follows the form:
>
> c(id_m[a],id_n[b],my_matrix[a,b])
>
> I can, of course, for-loop this thing with an if-then, e.g.:
>
> ***
>
> for (a in 1:length(id_m))
> {
> for (b in 1:length(id_n))
> {
> if ((a==1) && (b==1))
> {
> my_database=c(id_m[a],id_n[b],my_matrix[a,b])
> } else
> {
>
> my_database=rbind(my_database,c(id_m[a],id_n[b],my_matrix[a,b]))
> }
> }
> }
>
> ***
>
> But my gut is telling me this is an incredibly inefficient way of
> doing this -- is there a faster approach to doing this same process?
> Thanks!
>
> --j
>
> ______________________________________________
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