Dear all,
I am trying to avoid a for loop here and wonder if the following is possible:
I have a data.frame with 6 columns and i want to get a cross-correlogram (by
using ccf) . Obivously ccf only accepts two columns at once and then returms a
list.
In fact, with a for loop i´d do the following
for (i in 1:6) {
x[[i]]=ccf(mydf[,i],mydf[,6])
}
Is there any chance to the same with lapply? e.g. lapply(mydf,"ccf", .... )
with ... respresenting the changing arguments for ccf functions (note only the
first argument does actually change)
thx for any suggestions in advance
best
matt
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
