> ## Create a sample data. > data <- data.frame(father.id = letters[1:5], + diagnosis = sample(c(100,200,300,340),5,replace=TRUE), + diagnosis1 = sample(c(100,200,300,340),5,replace=TRUE), + diagnosis2 = sample(c(100,200,300,340),5,replace=TRUE)) > data father.id diagnosis diagnosis1 diagnosis2 1 a 340 100 300 2 b 200 300 340 3 c 200 300 100 4 d 200 100 300 5 e 200 100 100 > > ## Create a matrix by replicating the father.id column 3 times > ## Because we have 3 diagnosis columns to match when use table() function > match <- as.matrix(data[,rep(1:2,c(3,0))]) > match father.id father.id.1 father.id.2 [1,] "a" "a" "a" [2,] "b" "b" "b" [3,] "c" "c" "c" [4,] "d" "d" "d" [5,] "e" "e" "e" > > ## Count > table(match,as.matrix(data[,2:4])) match 100 200 300 340 a 1 0 1 1 b 0 1 1 1 c 1 1 1 0 d 1 1 1 0 e 2 1 0 0 >
Please refer to: http://r.789695.n4.nabble.com/Counting-Frequencies-in-Data-Frame-tt2221342.html#a2221487 http://r.789695.n4.nabble.com/Counting-Frequencies-in-Data-Frame-tt2221342.html#a2221487 ----- A R learner. -- View this message in context: http://r.789695.n4.nabble.com/Joining-two-or-more-frequency-tables-tp2222576p2222946.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.