On 15/05/2010 1:22 AM, Giovanni Azua wrote:
Hi Jorge and Dennis,
Thank you for the hint!
However, I'm still very intrigued as to why it does not work using plot ...
what is special about this specific formula that plot doesn't like it?
There's nothing special about the formula. plot() is simply saying (in
a slightly unclear way) that it requires an argument named x, and you
didn't pass one. You would get past that error by leaving off the
"formula =" part of your call, so that the first argument gets passed as
x by default. But then you'll get a new error:
>
plot(y~1/(1+exp(5.0993-0.1084*x)),data=data.frame(x=seq(0,100,length.out=1000)))
Error in eval(expr, envir, enclos) : object 'y' not found
The problem here is that you're asking to plot y versus an expression
involving x, without defining what y is. The version that works is the
slightly odd looking
> plot(1/(1+exp(5.0993-0.1084*x)) ~
x,data=data.frame(x=seq(0,100,length.out=1000)))
(or the version involving curve() that Jorge sent.)
Duncan Murdoch
Best regards,
Giovanni
On May 15, 2010, at 7:12 AM, Jorge Ivan Velez wrote:
Hi Giovanni,
curve(1/(1+exp(5.0993-0.1084*x)), 0, 100)
HTH,
Jorge
On Sat, May 15, 2010 at 12:43 AM, Giovanni Azua <> wrote:
Hello,
I'd like to plot the logistic function for a specific model like this:
plot(formula=y~1/(1+exp(5.0993-0.1084*x)),data=data.frame(x=seq(0,100,length.out=1000)))
Error in is.function(x) : 'x' is missing
However, I get the 'x' is missing error above and don't know how to fix it ...
Can anyone advice?
Thanks in advance,
Best regards,
Giovanni
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