See ?colSums On Mon, May 10, 2010 at 12:44 AM, vincent.deluard <vincent.delu...@trimtabs.com> wrote: > > Hi R users, > > I have a matrix "m" of the type: > > m > X4.20.2010 X4.19.2010 X4.16.2010 > [1,] 0.008319468 0.00000000 -0.008250825 > [2,] 0.005574136 0.01816118 0.073081608 > [3,] -0.047830688 0.01612903 -0.030239833 > [4,] NA NA NA > [5,] 0.008746356 0.02848576 -0.025566107 > [6,] -0.007990868 0.00000000 -0.026666667 > > I want to get the sum of each column. Normally I would do: > > apply(m,2,sum) > > but I get: > >> apply(m,2,sum) > X4.20.2010 X4.19.2010 X4.16.2010 > NA NA NA > > This is because of the presence of "NA" in m. How do you the equivalent of >> sum(m[1:6,1],na.rm=TRUE) > using apply? > > Many thanks! > -- > View this message in context: > http://r.789695.n4.nabble.com/tapply-function-with-NA-tp2164930p2164930.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
