The nchar and substring functions are both vectorized, you can do something like:
> substring(state.name, 1, nchar(state.name)-1) And it should be much faster. -- Gregory (Greg) L. Snow Ph.D. Statistical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r- > project.org] On Behalf Of Sebastian Kruk > Sent: Friday, April 30, 2010 4:45 PM > To: r-help@r-project.org; r-h...@stat.math.ethz.ch > Subject: [R] drop last character in a names'vector > > Hi, i have a vector filled with names: > > [1] Alvaro Adela ... > [25] Beatriz Berta ... > ... > [100000] ... > > I would like to drop last character in every name. > > I use the next program: > > for (i in 1:100000) { > largo <- nchar(names[i]-1) > names[i] <- substring (names[i],1,largo] > } > > Is another and faster way of do it? > > Thanks, > > Sebastián. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
