On Apr 26, 2010, at 11:27 AM, Gabor Grothendieck wrote:

Here are four ways:

# state.name comes with R
DF <- data.frame(state = state.name, num = seq_along(state.name))

DF[DF$state %in% c("Iowa", "Utah"),]

subset(DF, state %in% c("Iowa", "Utah"))

subset(DF, grepl("Iowa|Utah", state))

John;

The grepl implementation offers benefits that the %in% versions do not, e.g. partial matches:

 subset(DF, grepl("New+", state))
           state num
29 New Hampshire  29
30    New Jersey  30
31    New Mexico  31
32      New York  3

Or equivalently and probably faster:

> DF[grepl("New+", DF$state), ]

This gives the state.names with any spaces:
> DF[grepl(". +", DF$state), ]
--
David.

library(sqldf) # see http://sqldf.googlecode.com
sqldf("select * from DF where state in ('Iowa', 'Utah')")


On Mon, Apr 26, 2010 at 11:12 AM, John Sorkin
<jsor...@grecc.umaryland.edu> wrote:
I would like to select rows if a row contains any one of several values. I can do the selection as follows:

result[,"Subject"]=="JEFF" | result[,"Subject"]=="BG"

But this is very unwieldily if one wishes to select many, many rows as one has to continuously repeat the source:

result[,"Subject"]=="JEFF" | result[,"Subject"]=="BG" | result[,"Subject"]=="John" | result[,"Subject"]=="Mary"

Is there an easier way? I tried the following but it did not work:


result[,"Subject"]==c("JEFF" | "BG" | "John"  | "Mary")

Thanks,
John



John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call phone number above prior to faxing)

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