On Apr 19, 2010, at 9:12 AM, Downey, Patrick wrote:
Hi Thierry,
That worked perfectly. Thanks for the suggestion.
For reference, in the documentation, it
What is "it"?
never lists {Hmisc}'s function as
starting with E instead of e.
Every instance of the documentation in the r help system using ??ecdf
that I can find for Hmisc's version has it properly capitalized. I
have Hmisc_3.7-0
I don't know who's in charge of
documentation
It would be the package maintainer if there were a problem.
, but that
What is "that"?
--
David
should probably be corrected.
Thanks again.
-Mitch
-----Original Message-----
From: ONKELINX, Thierry [mailto:thierry.onkel...@inbo.be]
Sent: Monday, April 19, 2010 9:08 AM
To: Downey, Patrick; R help
Subject: RE: [R] ecdf
R is case sensitive. ecdf() is in the stats package, Ecdf() is in
Hmisc.
So you want Ecdf(x,what='1-F')
Thierry
------------------------------------------------------------------------
----
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
team Biometrics & Quality Assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
thierry.onkel...@inbo.be
www.inbo.be
To call in the statistician after the experiment is done may be no
more
than asking him to perform a post-mortem examination: he may be able
to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data.
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ensure that a reasonable answer can be extracted from a given body of
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-----Oorspronkelijk bericht-----
Van: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] Namens Downey, Patrick
Verzonden: maandag 19 april 2010 15:04
Aan: R help
Onderwerp: [R] ecdf
Hello,
I'd like to plot an empirical cumulative distribution
function, except instead of the fraction of values < x, I'd
like the fraction of values > x.
I think this can be done using the ecdf function in {Hmisc}.
I installed the package and loaded it. However, when
following the example given in the documentation, I get an error:
x <- rnorm(100)
ecdf(x,what='1-F')
Error in ecdf(x, what = "1-F") : unused argument(s) (what = "1-F")
I believe that this is because R is attempting to access the
ecdf function in base R, which does not have the what option.
Am I correct, and if so, how can I change that?
Note: I also tried to "do it myself" without the {Hmisc} ecdf
function, and couldn't figure out a way.
x2 <- 1-ecdf(x)
doesn't work, and neither does
x2 <- rep(0,times=100)
for(i in 1:100){
x2[i] <- 1-ecdf(x)[i]
}
Both result in errors.
Thanks in advance for any suggestions you can offer.
-Mitch
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