On Apr 8, 2010, at 7:39 AM, Lee William wrote:
Hello! All,
I am working on 10000x1000 matrix say 'mat' and i want to subset
this matrix
in a fashion that in new matrix i get columns
2,3,9,10,16,17,23,24.......so
on. That is pair of columns after every interval of 7. I tried
following but
i got an error which is obvious.
a <- mat[ , sort( c(seq(2, 1000, by=7), 1 +seq(2, 1000, by=7)))]
dim(mat)
[1] 10000 10
a=mat[,c(seq(c(2,3),ncol(mat),7))]
Warning messages:
1: In if (n < 0L) stop("wrong sign in 'by' argument") :
the condition has length > 1 and only the first element will be used
2: In if (n > .Machine$integer.max) stop("'by' argument is much too
small")
:
the condition has length > 1 and only the first element will be used
3: In if (dd < 100 * .Machine$double.eps) return(from) :
the condition has length > 1 and only the first element will be used
4: In 0L:n : numerical expression has 2 elements: only the first used
Is there any other way to do it?? Please, help!
regards
Lee
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