On Apr 5, 2010, at 5:25 PM, David Winsemius wrote: > > On Apr 5, 2010, at 4:58 PM, Ayush Raman wrote: > >> Hi all, >> >> How can I have a permuted matrix where the second row is the permutation >> over the first row ; third is the permutation of the second row; forth is >> the permutation of the third row and so on ? > > Wouldn't any of those permutations just be a permutation of the first row? > Perhaps something like: > > > M <- matrix(first_row, length(first_row), length(first_row)) > M[1, ] <- first_row > M[2:length(first_row), ] <- rbind( > t(sapply(2:length(first_row), function(x) { > sample(first_row, length(first_row), replace=FALSE) } > ) ) > )
How about something like this: # set first row entries row1 <- 1:6 # Total desired rows, including above totalrows <- 5 set.seed(1) > rbind(row1, t(replicate(totalrows - 1, sample(row1))), deparse.level = 0) [,1] [,2] [,3] [,4] [,5] [,6] [1,] 1 2 3 4 5 6 [2,] 2 6 3 4 1 5 [3,] 6 4 3 1 5 2 [4,] 5 2 4 6 3 1 [5,] 3 4 5 1 2 6 ? HTH, Marc Schwartz ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.