Kenneth Roy Cabrera Torres <krcabrer <at> une.net.co> writes:
> Hi R users:
> I found that I cannot stack() a data.frame with factors.
> db1<-data.frame(replicate(6,factor(sample(c("A","B"),6,replace=TRUE))))
> str(db1)
> db2<-stack(db1)
> db2
> "db2" does not have any row.
> How can I stack them by the variables X1,X2,...,X6?you can see what is happening in stack.data.frame you have a line x <- x[, unlist(lapply(x, is.vector)), drop = FALSE] and lapply(x, is.vector)) is applied to each column of the data frame but you can verify for yourself that a factor yields FALSE here x <- db1[[1]] is.vector(x) [1] FALSE so I think that this at least explains why it doesn't work as you expected. > Thank you for your help. > > Kenneth -- Ken Knoblauch Inserm U846 Stem-cell and Brain Research Institute Department of Integrative Neurosciences 18 avenue du Doyen Lépine 69500 Bron France tel: +33 (0)4 72 91 34 77 fax: +33 (0)4 72 91 34 61 portable: +33 (0)6 84 10 64 10 http://www.sbri.fr/members/kenneth-knoblauch.html ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
