> Run that function hourly with plyr > > output.hourly <- dlply(df.i1,"tshour",cor.dat)
Why not output.hourly <- ddply(df.i1,"tshour",cor.dat) ? Generally you want to work with data frames in R, if at all possible. Hadley -- Assistant Professor / Dobelman Family Junior Chair Department of Statistics / Rice University http://had.co.nz/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
