Apparently the vectors that I have are lists and when I try to conduct the 
Bartlett test I am getting errors. I may be using it wrong. I am not an R 
expert>

xbartlett2 <- c(Samp1,Samp2)
#Samp1 & 2 are lists
gbartlett24 <- c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 
2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2)

Attempt 1
> gazant <- bartlett.test(xbartlett2~gbartlett24)$p.value
Error in model.frame.default(formula = xbartlett2 ~ gbartlett24) : 
  invalid type (list) for variable 'xbartlett2'

xbartlett2 <- c(Samp1,Samp2)



> gazant <- bartlett.test(xbartlett2, gbartlett24)$p.value
Error in bartlett.test.default(xbartlett2, gbartlett24) : 
  there must be at least 2 observations in each group

(There are at least 2 unique observations in each group)

Thanks in advance





----- Original Message ----
From: "Richardson, Patrick" <patrick.richard...@vai.org>
To: Amit Patel <amitrh...@yahoo.co.uk>; "r-help@r-project.org" 
<r-help@r-project.org>
Sent: Mon, 1 March, 2010 14:31:15
Subject: RE: [R] Bartlett Test

?bartlett.test

>From the help page "If x is a list, its elements are taken as the samples or 
>fitted linear models to be compared for homogeneity of variances. In this 
>case, the elements must either all be numeric data vectors or fitted linear 
>model objects, g is ignored, and one can simply use bartlett.test(x) to 
>perform the test. If the samples are not yet contained in a list, use 
>bartlett.test(list(x, ...)). 

Otherwise, x must be a numeric data vector, and g must be a vector or factor 
object of the same length as x giving the group for the corresponding elements 
of x. "

Patrick

-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of Amit Patel
Sent: Monday, March 01, 2010 9:26 AM
To: r-help@r-project.org
Subject: [R] Bartlett Test

Hi 

I am trying to conduct a Bartlett test between two groups Samp 1 and Samp 2, 
both of which are vectors of equal length. I cant find any information on how 
to do this. Does the data need to be in a structured list. 

Thanks in advance





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