Try this: names(o...@x.values)
On Mon, Feb 22, 2010 at 11:05 AM, Jay <josip.2...@gmail.com> wrote: > The function prediction() returns this: > > Formal class 'performance' [package "ROCR"] with 6 slots > ..@ x.name : chr "Cutoff" > ..@ y.name : chr "Accuracy" > ..@ alpha.name : chr "none" > ..@ x.values :List of 1 > .. ..$ : Named num [1:89933] Inf 2.23 2.22 2.17 2.16 ... > .. .. ..- attr(*, "names")= chr [1:89933] "" "36477" "56800" > "41667" ... > ..@ y.values :List of 1 > .. ..$ : num [1:89933] 0.5 0.5 0.5 0.5 0.5 ... > ..@ alpha.values: list() > > Now, since I want to match each prediction with its original case, I > need to extract the names, i.e. the information in "- attr(*, > "names")= chr [1:89933] "" "36477" "56800" "41667" ..." so I can use > it with a simple datafile[names,] query. > > How do I get these names in plain number formats? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
