Hi, see the code below. Next time, please provide self-contained code to generate the matrix (read the posting guide) so that we can just copy-paste it into R to get the matrix.
x=rep(c(0,1),4) y=rep(c(0,0,1,1),2) z=rep(c(0,1),each=4) m=cbind(z,y,x) w=rowSums(m) m=cbind(m,w) m m[order(w,x,y,z),] HTH, Daniel ------------------------- cuncta stricte discussurus ------------------------- -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Evgenia Sent: Friday, February 19, 2010 12:10 PM To: r-help@r-project.org Subject: [R] inverse lexicographical ordering Dear users, I have a matrix b as [,1] [,2] [,3] [,4] [1,] 0 0 0 0 [2,] 0 0 1 1 [3,] 0 1 0 1 [4,] 0 1 1 2 [5,] 1 0 0 1 [6,] 1 0 1 2 [7,] 1 1 0 2 [8,] 1 1 1 3 with last column the rowSums(b) I want for each value of last column of b separately (b:0,1,2,3, to sort the above table by reverse lexicographical order. For the above table the result should be 1 0 0 0 2 1 0 0 3 0 1 0 4 0 0 1 5 1 1 0 6 1 0 1 7 0 1 1 8 1 1 1 Could anyone help me with this? Thanks alot Evgenia -- View this message in context: http://n4.nabble.com/inverse-lexicographical-ordering-tp1561930p1561930.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.