Jonathan -
split will do what you want:
df <- data.frame('id'=c('a','b','a','c','b','a'),'value'=c(6,4,2,9,1,7))
split(df$value,df$id)
$a
[1] 6 2 7
$b
[1] 4 1
$c
[1] 9
Thanks for providing a reproducible example!
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Fri, 12 Feb 2010, Jonathan Reichel wrote:
Hi all,
Another one:
Given a data frame with two columns, where the first column (let's
call it 'id') has redundant entries, I'd like to get, for each unique
value in 'id', a list or vector of all the values from the second
column that corresponded to that value.
Example:
df <- data.frame('id'=c('a','b','a','c','b','a'),'value'=c(6,4,2,9,1,7))
df
id value
1 a 6
2 b 4
3 a 6
4 c 9
5 b 1
6 a 7
I'd like some kind of output resembling something along these lines:
a: 6, 6, 7
b: 4, 1
c: 9
Any ideas would be appreciated!
Best,
Jonathan
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