This seems to work fine for me:
> x <- read.table(textConnection(" Date trade_day IV.b IV.a
+ 1 2003-03-02 19 0.1724818 0.1815687
+ 2 2003-03-02 18 0.1733542 0.1763827
+ 3 2003-03-02 19 0.1753308 0.1783653
+ 4 2003-03-03 16 0.1751217 0.1781624
+ 5 2003-03-03 16 0.1738580 0.1768961
+ 6 2003-03-03 19 0.1733346 0.1763800"), header=TRUE)
> closeAllConnections()
> split(x, list(x$Date, x$trade_day), drop=TRUE)
$`2003-03-03.16`
Date trade_day IV.b IV.a
4 2003-03-03 16 0.1751217 0.1781624
5 2003-03-03 16 0.1738580 0.1768961
$`2003-03-02.18`
Date trade_day IV.b IV.a
2 2003-03-02 18 0.1733542 0.1763827
$`2003-03-02.19`
Date trade_day IV.b IV.a
1 2003-03-02 19 0.1724818 0.1815687
3 2003-03-02 19 0.1753308 0.1783653
$`2003-03-03.19`
Date trade_day IV.b IV.a
6 2003-03-03 19 0.1733346 0.17638
>
On Sun, Jan 31, 2010 at 2:25 PM, Ted Zeng (曾振兴) <zengzhenx...@gmail.com> wrote:
>
> Dear R users:
>
> I am dealing a data frame x as followings:
>
> Date trade_day IV.b IV.a
> 1 2003-03-02 19 0.1724818 0.1815687
> 2 2003-03-02 18 0.1733542 0.1763827
> 3 2003-03-02 19 0.1753308 0.1783653
> 4 2003-03-03 16 0.1751217 0.1781624
> 5 2003-03-03 16 0.1738580 0.1768961
> 6 2003-03-03 19 0.1733346 0.1763800
> ......
>
> I want to split the data flame into groups according to the variable "Date"
> and "trade_day"
> I tried: split(x,f=list(a=x$Date,b=x$trade_day)), but it doesn't work. How
> can I solve this problem?
>
> Thanks advance
>
> Ted
> --
> View this message in context:
> http://n4.nabble.com/How-to-split-data-frame-into-groups-by-a-list-of-factors-tp1458171p1458171.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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