for (i in c('aum', 'num','aum.core','num.core')) t[[i]][is.na(t[[i]])] <- 0On Sat, Jan 30, 2010 at 3:34 PM, Dimitri Shvorob <dimitri.shvo...@gmail.com> wrote: > > How can one simplify the folowing? > > t$aum[is.na(t$aum)] = 0; t$aum.core[is.na(t$aum.core)] = 0 > t$num[is.na(t$num)] = 0; t$num.core[is.na(t$num.core)] = 0 > > Thank you. > -- > View this message in context: > http://n4.nabble.com/Applying-a-transformation-to-multiple-data-frame-columns-tp1457641p1457641.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
