Classification: UNCLASSIFIED Caveats: NONE Dear R users, How can I retrieve an evaluated gradient value from "deriv" function provided below? I want to retrieve b0 value. Appreciate your help.
Kyong junk1<-deriv(~(1/b1)*k-b0/b1,"b0",c("k","b0","b1"),formal=T) junk1(k=0,b0=-14.0236,b1=2.44031) [1] 5.746647 attr(, "gradient"): b0 [1,] -0.409784 Classification: UNCLASSIFIED Caveats: NONE [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.