Tena koe Jim
You could use unlist and matrix. For example:
> tempList
[[1]]
[1] "a" "A"
[[2]]
[1] "b" "B"
[[3]]
[1] "c" "C"
> unlist(tempList)
[1] "a" "A" "b" "B" "c" "C"
> matrix(unlist(tempList), nrow=3)
[,1] [,2]
[1,] "a" "B"
[2,] "A" "c"
[3,] "b" "C"
> matrix(unlist(tempList), nrow=3, byrow=T)
[,1] [,2]
[1,] "a" "A"
[2,] "b" "B"
[3,] "c" "C"
> matrix(unlist(tempList), nrow=3, byrow=T)[,1]
[1] "a" "b" "c"
HTH ....
Peter Alspach
> -----Original Message-----
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of James Rome
> Sent: Tuesday, 19 January 2010 10:49 a.m.
> To: r-help@r-project.org
> Subject: [R] Using the output of strsplit
>
> I successfully combined my data frames, and am now on my next hurdle.
>
> I had combined the data and quarter, and used tapply to count
> the entries for each unique date/quarter pair.
> ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum) #for each date/quarter
> combination sums the gw (which are all 1)
> dq=row.names(ar)
> spl=strsplit(dq)
> But I need to split them back into the separate date and
> quarter. So I used strsplit(), and get
> > spl
> [[1]]
> [1] "2009-01-01" "60"
>
> [[2]]
> [1] "2009-01-01" "61"
>
> [[3]]
> [1] "2009-01-01" "62"
>
> [[4]]
> [1] "2009-01-01" "63"
>
> [[5]]
> [1] "2009-01-01" "68"
> . . .
>
> But lists throw me. I want to get separate vectors of the
> date and quarter out of my list. All the things I have seen
> extract rows from the list. I need to extract columns.
>
> Thanks list,
> Jim Rome
>
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