Try this: glm(y ~ ., family = binomial, data = data, ...)
On Tue, Jan 12, 2010 at 9:45 AM, npobedina <npobed...@gmail.com> wrote: > > Hi! > I'm trying to run logistic regression on a dataset which is contained in > dataframe "data" ("y" is in the first col, and 28 parameters for the model). > How can I write formula for function `glm` without listing explicitly all 28 > paramaters? > `glm(data[,1]~data[,2]+data[,3]+data[,4]+...,family=binomial)` > > As an option I can use `glm.fit(data[,-1],data[,1],family = > binomial(link=logit))`. But the obtained object cannot be used in function > `predict.glm`. > > Thanks, > Natalia > -- > View this message in context: > http://n4.nabble.com/List-arguments-from-data-frame-columns-in-formula-tp1012146p1012146.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.