try using 'grepl'
> if( grepl("hi", "hop", fixed = TRUE) ){
+ print('yes, your substring is in your string')
+ } else print('no, your substring is not in your string')
[1] "no, your substring is not in your string"
>
On Sat, Dec 19, 2009 at 3:47 PM, Jonathan <jonsle...@gmail.com> wrote:
> Hi,
> A noobie question: I'm simply trying to run a conditional statement that
> evaluates if a substring is found within a larger string. I find that if
> it
> IS found, my function returns TRUE (great!), but if not, the condition does
> not evaluate to FALSE.
>
> ex):
>
> if( grep("hi", "hop", fixed = TRUE) )
> print('yes, your substring is in your string')
> else print('no, your substring is not in your string')
>
> alternatively, I could replace grep with pmatch:
>
> if (pmatch('hi','hop'))
> print('yes, your substring is in your string')
> else print('no, your substring is not in your string')
>
>
> The first example, using grep, returns logical(0). The second, using
> pmatch, returns NA. Any idea how to convert either of those to FALSE, or
> else a different function that would do the trick?
>
> Thanks,
> Jon
>
> [[alternative HTML version deleted]]
>
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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