Here a way of doing it:
for (i in 5:12){
# convert to character so you can substitute 'x'
a <- as.character(dd[,i])
a[a == 'x'] <- '0' replace with zero
dd[,i] <- as.numeric(a)
}
On Fri, Dec 4, 2009 at 11:55 AM, Allen L <allen.laroc...@gmail.com> wrote:
>
> Dear R forum,
> I want to replace all the elements in a data frame (dd) which match the
> character "x" with "0".
> What's the most elegant way of doing this (there must be an easy way which
> I've missed)? I settled on the following loop:
>
> >for(i in 5:12){ # These are the column of dd I am
> interested
> in
> >dd[which(dd[,i]=="x"),i]<-0
> >}
>
> The problem with this is that the columns which used to contain "x" are
> still considered factors and I am unable to coerce them into numeric:
>
> > mean.species.biomass<-colMeans(as.numeric(dd.p[,5:12]))
> >Error in inherits(x, "data.frame") :
> (list) object cannot be coerced to type 'double'
>
> I'm tried unclassing & reclassing, other functions etc. but nothing seems
> to
> work. What is wrong?
> Thanks in advance,
> Allen
> --
> View this message in context:
> http://n4.nabble.com/Class-attributes-tp948693p948693.html
> Sent from the R help mailing list archive at Nabble.com.
>
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> PLEASE do read the posting guide
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>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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