Andreas Wittmann <andreas_wittmann <at> gmx.de> writes: > > Dear R-users, > > i try to solve to following linear programm in R > > 0 * x_1 + 2/3 * x_2 + 1/3 * x_3 + 1/3 * x_4 = 0.3 > x_1 + x_2 + x_3 + x_4 = 1 > x_1, x_2, x_3, x_4 > 0, > x_1, x_2, x_3, x_4 < 1 > > as you can see i have no objective function here besides that i use the > following code. > > library(lpSolve) > > f.obj<-c(1,1,1,1) > f.con<-matrix(c(0,2/3,1/3,1/3, > 1,1,1,1, > 1,0,0,0, > 0,1,0,0, > 0,0,1,0, > 0,0,0,1),nrow=6,byrow=TRUE) > f.dir <- c("=", "=", ">", ">", ">", ">") > f.rhs <- c(0.3, 1, 0, 0, 0, 0) > > lp ("max", f.obj, f.con, f.dir, f.rhs)$solution > > the problem is, the condition x_1, x_2, x_3, x_4 > 0 is not fulfilled.
With strict inequalities x_i > 0 your problem will not have a solution. That is why in linear programming strict inequalities are replaced with non-strict inequalities, or as the lp_solve manual says: "The inequalities can be <=, >= or = Because all numbers are real values, <= is the same as < and >= is the same as > ." Try x_i >= eps > 0 with some eps appropriate for your problem. Hans Werner > Any advice would be very helpful. > > best regards > > Andreas > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.