The term "line" in R refers to a sequence of text ending in and
<EOL> marker, which I doubt is what you meant. Please stop referring
to the items or elements of a list as "lines" if you hope to
communicate with R-users.
> lista[1:2]
[[1]]
[1] 2 4 5 5 6
[[2]]
[1] 3 5 4 2
> lista[ which(sapply(lista, function(x) any(x == 5))) ]
[[1]]
[1] 2 4 5 5 6
[[2]]
[1] 3 5 4 2
--
David.
On Nov 15, 2009, at 11:57 AM, Grzes wrote:
It's excellent!
Now, if I have a vector k=c( TRUE, TRUE, FALSE) how I may get lines
from
list?
which (list ?? k) ?
David Winsemius wrote:
On Nov 15, 2009, at 10:47 AM, Grzes wrote:
But it's not what I wont
I need get a number of line my list
5 is in: list[[1]][1] and list[[2]][1] so
I would like to get a vector k = 1,2
I am sorry. I do not understand what you want the second solution
offered gave you numbers (and they were the numbers that were for
"5"'s rather than one that were not for "5"'s as your offered
solution.
If you just want to know which lists contain a 5, but not the
position
within the list (which was not what you appeared to be asking..):
which(sapply(lista, function(x) any(x == 5)))
[1] 1 2
David Winsemius wrote:
On Nov 15, 2009, at 10:01 AM, Grzes wrote:
I heve got a list:
lista=list()
a=c(2,4,5,5,6)
b=c(3,5,4,2)
c=c(1,1,1,8)
lista[[1]]=a
lista[[2]]=b
lista[[3]]=c
lista
[[1]]
[1] 2 4 5 5 6
[[2]]
[1] 3 5 4 2
[[3]]
[1] 1 1 1 8
I would like to know where is number 5 (which line)?
For example I have got a loop:
k= vector(mode = "integer", length = 3)
for(i in 1:3)
{
for (j in 1:length(lista[[i]])){
if ((lista[[i]][j])==5 k[i]= [i])
}
}
This loop is wrong but I would like to get in my vector k sth like
this:
k = lista[[1]][1], lista[[2]][1] ...or sth similar
I am a bit confused, since clearly lista[[1]][1] does _not_ == 5.
It's
also unclear what type of output you expect ... character, list,
numeric?
See if these take you any further to your vaguely expressed goal:
lapply(lista, "%in%", 5)
[[1]]
[1] FALSE FALSE TRUE TRUE FALSE
[[2]]
[1] FALSE TRUE FALSE FALSE
[[3]]
[1] FALSE FALSE FALSE FALSE
lapply(lista, function(x) which(x == 5) )
[[1]]
[1] 3 4
[[2]]
[1] 2
[[3]]
integer(0)
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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