Jim Holtman,
Thank you for your reply.
Your script is very concise and I think it could help me.
However when I run it on my real data object (musigma.lat.m) the age range from
5-50 skips certain full years (see script below).
Am not sure why that is and no error is given.
Hoping you can help.
Thank you in advance for your time and energy.
All the best,
Daniel
> dput(musigma.lat.m[580:620,])
structure(list(age = c(48.25, 48.3333333333333, 48.4166666666667,
48.5, 48.5833333333333, 48.6666666666667, 48.75, 48.8333333333333,
48.9166666666667, 49, 49.0833333333333, 49.1666666666667, 49.25,
49.3333333333333, 49.4166666666667, 49.5, 49.5833333333333, 49.6666666666667,
49.75, 49.8333333333333, 49.9166666666667, 50, 0, 0.0833333333333333,
0.166666666666667, 0.25, 0.333333333333333, 0.416666666666667,
0.5, 0.583333333333333, 0.666666666666667, 0.75, 0.833333333333333,
0.916666666666667, 1, 1.08333333333333, 1.16666666666667, 1.25,
1.33333333333333, 1.41666666666667, 1.5), country = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("Bolivia", "Brazil",
"Colombia", "Dominican Rep.", "El Salvador", "Guatemala", "Guyana",
"Haiti", "Honduras", "Nicaragua", "Paraguay", "Peru", "Suriname"
), class = "factor"), mu = c(10.7198320154036, 10.7193221119285,
10.7188036231439, 10.7182764259851, 10.7177406001273, 10.7171962535812,
10.7166435245754, 10.7160826629999, 10.7155141252060, 10.7149385933270,
10.7143568116012, 10.7137696820872, 10.7131779280271, 10.7125822168258,
10.7119832145823, 10.7113816139594, 10.7107780960397, 10.7101732860418,
10.7095677728307, 10.7089620284128, 10.7083564497153, 10.7077512971194,
11.548875536071, 11.4634458099448, 11.4113675486745, 11.3384424250672,
11.2435706626324, 11.1313969585720, 11.0086560681222, 10.8827443523793,
10.7598371816865, 10.6440424747848, 10.5382165128003, 10.4442220905656,
10.3633207905823, 10.2961499250469, 10.2427320635721, 10.2025802100475,
10.1749531325293, 10.1590477762319, 10.1540156426321), sigma =
c(0.0947487228789027,
0.0947760295260326, 0.0948033853581562, 0.0948307832769866, 0.094858216728106,
0.0948856796527442, 0.0949131660004063, 0.0949406718763748, 0.0949681949273155,
0.0949957322607503, 0.0950232806230888, 0.095050836445582, 0.0950783958990592,
0.0951059550037287, 0.0951335102859937, 0.0951610590705954, 0.0951885984623664,
0.0952161256367413, 0.0952436392777666, 0.0952711384472643, 0.0952986226318235,
0.0953260918098295, 0.108394172852678, 0.112555919942990, 0.114345649992535,
0.115763779372203, 0.116984886895669, 0.118065092089138, 0.119029362771532,
0.119887968678076, 0.120638553936562, 0.121278180095107, 0.121810743569063,
0.122245010348365, 0.122590801228219, 0.122858869689557, 0.123059216409329,
0.123199542683827, 0.123286339009648, 0.123324768295488, 0.123319375423601
)), .Names = c("age", "country", "mu", "sigma"), row.names = c("580",
"581", "582", "583", "584", "585", "586", "587", "588", "589",
"590", "591", "592", "593", "594", "595", "596", "597", "598",
"599", "600", "601", "602", "603", "604", "605", "606", "607",
"608", "609", "610", "611", "612", "613", "614", "615", "616",
"617", "618", "619", "620"), class = "data.frame")
>
> result <- lapply(split(musigma.lat.m, musigma.lat.m$country), function(.ctry){
+ # keep all < 5 and only integers over 5
+ subset(.ctry, .ctry$age < 5 | .ctry$age %in% 5:50)
+ })
>
> result
$Bolivia
age country mu sigma
1 0.00000000 Bolivia 11.42168 0.10148719
2 0.08333333 Bolivia 11.33625 0.10538375
3 0.16666667 Bolivia 11.28417 0.10705943
4 0.25000000 Bolivia 11.21125 0.10838720
5 0.33333333 Bolivia 11.11637 0.10953050
...
59 4.83333333 Bolivia 10.49080 0.10671819
60 4.91666667 Bolivia 10.48562 0.10653400
109 9.00000000 Bolivia 10.43279 0.10180158
133 11.00000000 Bolivia 10.33394 0.10160484
169 14.00000000 Bolivia 10.24878 0.09946659
193 16.00000000 Bolivia 10.20148 0.09694376
205 17.00000000 Bolivia 10.16589 0.09573946
$Brazil
age country mu sigma
602 0.00000000 Brazil 11.54888 0.10839417
603 0.08333333 Brazil 11.46345 0.11255592
604 0.16666667 Brazil 11.41137 0.11434565
605 0.25000000 Brazil 11.33844 0.11576378
...
660 4.83333333 Brazil 10.61799 0.11398118
661 4.91666667 Brazil 10.61281 0.11378445
710 9.00000000 Brazil 10.55999 0.10872996
734 11.00000000 Brazil 10.46113 0.10851983
770 14.00000000 Brazil 10.37597 0.10623606
794 16.00000000 Brazil 10.32867 0.10354153
-----Original Message-----
From: jim holtman [mailto:jholt...@gmail.com]
Sent: 04 November 2009 03:12
To: Hayes, Daniel
Cc: r-h...@lists.r-project.org
Subject: Re: [R] creating mulptiple new variables from one data.frame according
to columns and rows in that frame
try this:
> x <- read.table(textConnection(" Age(yrs) country mu sigma
+ 1 0.00000000 Bolivia 11.42168 0.1014872
+ 2 0.08333333 Bolivia 11.33625 0.1053837
+ 3 0.16666667 Bolivia 11.28417 0.1070594
+ 4 0.25000000 Bolivia 11.21125 0.1083872
+ 5 0.33333333 Bolivia 11.11637 0.1095305
+ 5.1 5 Bolivia 11.11637 0.1095305
+ 5.2 5.5 Bolivia 11.11637 0.1095305
+ 5.3 6 Bolivia 11.11637 0.1095305
+ 5.4 20 Bolivia 11.11637 0.1095305
+ 5.5 20.1 Bolivia 11.11637 0.1095305
+ 5.6 50 Bolivia 11.11637 0.1095305
+ 602 0.00000000 Brazil 11.54888 0.10839417
+ 603 0.08333333 Brazil 11.46345 0.11255592
+ 604 0.16666667 Brazil 11.41137 0.11434565
+ 605 0.25000000 Brazil 11.33844 0.11576378
+ 606 0.33333333 Brazil 11.24357 0.11698489"), header=TRUE)
> closeAllConnections()
> result <- lapply(split(x, x$country), function(.ctry){
+ # keep all < 5 and only integers over 5
+ subset(.ctry, .ctry$Age.yrs. < 5 | .ctry$Age.yrs. %in% 5:50)
+ })
>
> result
$Bolivia
Age.yrs. country mu sigma
1 0.00000000 Bolivia 11.42168 0.1014872
2 0.08333333 Bolivia 11.33625 0.1053837
3 0.16666667 Bolivia 11.28417 0.1070594
4 0.25000000 Bolivia 11.21125 0.1083872
5 0.33333333 Bolivia 11.11637 0.1095305
5.1 5.00000000 Bolivia 11.11637 0.1095305
5.3 6.00000000 Bolivia 11.11637 0.1095305
5.4 20.00000000 Bolivia 11.11637 0.1095305
5.6 50.00000000 Bolivia 11.11637 0.1095305
$Brazil
Age.yrs. country mu sigma
602 0.00000000 Brazil 11.54888 0.1083942
603 0.08333333 Brazil 11.46345 0.1125559
604 0.16666667 Brazil 11.41137 0.1143456
605 0.25000000 Brazil 11.33844 0.1157638
606 0.33333333 Brazil 11.24357 0.1169849
On Tue, Nov 3, 2009 at 9:31 AM, Hayes, Daniel <d.j.ha...@liverpool.ac.uk> wrote:
> Dear R-helpers,
>
> I have a data.frame (bcpe.lat.m) containing 13 countries, ages 0-50yrs per
> month, and the corresponding mu&sigma (see below).
>
> * I would like to limit the age range to include all 12 months for the
> 1st 5 years and only whole years for all ages thereafter for each of the
> countries present in the data frame.
>
> * I would like to create separate data.frames according to the country
> the data is from (Bolivia.bcpe.lat.m, brazil.bcpe.lat.m, etc)
>
>
> I have tried using: c(seq(0,5,1/12),seq(5,50,1) ) to select the desired
> ages but am unsure how to repeat that sequence for consecutive countries.
> I have tried using: split(bcpe.lat.m, bcpe.lat.m$country) But end up with a
> string which I am no longer to select the specific ages I want and all the
> data still remains in one variable
> Have also looked a 'by', 'apply' and things like 'for (i in 1:13)'
>
> Help with either or both steps would be greatly appreciated.
>
> Greetings from Formentera,
> Daniel
>
> Age(yrs) country mu sigma
> 1 0.00000000 Bolivia 11.42168 0.1014872
> 2 0.08333333 Bolivia 11.33625 0.1053837
> 3 0.16666667 Bolivia 11.28417 0.1070594
> 4 0.25000000 Bolivia 11.21125 0.1083872
> 5 0.33333333 Bolivia 11.11637 0.1095305
> ...
> 602 0.00000000 Brazil 11.54888 0.10839417
> 603 0.08333333 Brazil 11.46345 0.11255592
> 604 0.16666667 Brazil 11.41137 0.11434565
> 605 0.25000000 Brazil 11.33844 0.11576378
> 606 0.33333333 Brazil 11.24357 0.11698489
> ...
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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