If the 'data set' is a dataframe, the following will work: x$v1 <- ifelse(x$p > 0.4, 1, 0) x$v2 <- ifelse(x$p > 0.6, 1, 0)
If it is matrix, try x <- cbind(x, v1=ifelse(x[,'p'] > 0.4, 1, 0), v2=ifelse(x[,'p'] > 0.6, 1, 2)) If helps a lot if you follow the posting rules and provide commented, minimal, self-contained, reproducible code. On Sat, Oct 10, 2009 at 6:04 PM, Ashta <sewa...@gmail.com> wrote: > Hi all, > > I have a data set called x with 200 rows and 12 columns. I want > create two more columns based on probability. ie > if p >0 .4 then v1 =1 else v1=0; > if p >0 .6 then v2 =1 else v2=0; > > Finally x will have 14 variables. > > Can any one show me how to do that? > > Thanks > Ashta > > > . > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
