Hi Marlene, x=data.frame(y,vr=NA) for(i in 4:nrow(x)) x[i,"vr"] =var(y[(i-3):(i-1)])
will do the trick, solving both problems with overwriting subsequent x-values and obeying the precedence of R operators.
For the latter, see ?Syntax and compare i<-5 i-3:i-1 (i-3):(i-1) hth. marlene marchena schrieb:
Dear R-user Suppose I have the following data y=c(2,1,5,8,11,3,1,7,50,21,33,7,60) x=data.frame(y) for(i in 4:nrow(x)) x[i,] =var(x[i-3:i-1,]) I'm trying to get a new variable with the variance of the 3 previous values (just an example) and with NA in the three first positions. I know that my for() is wrong but I'm not able to find my error. Any idea? Thanks, Marlene. [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
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