I think these examples will show what one can and cannot do with the
invisible function.
> f2 <- function(x,y) return(c(x, invisible(x^y)) )
> f2(2,2)
[1] 2 4 #so that not the right way to keep tree hidden
> f2 <- function(x,y) invisible(c(print(x),(x^y)) )
> f2(2,2)
[1] 2 # success x^y is calculate but not made visible on return
> print(f2(2,2))
[1] 2 # that came from within the f2 function
[1] 2 4 # that is what the value returned by f2
On Sep 20, 2009, at 11:21 AM, David Winsemius wrote:
On Sep 20, 2009, at 10:59 AM, manta wrote:
Good afternoon,
I know it is a simple question but I cannot figure out how to solve
this
issue.
I have a function that calculate two objects. I would like to choose
everytime about the tree object, with default to not show it.
I cannot understand that. Perhaps you can try again to tell us what
you want to do with tree?
OP<-function(S=100,X,sigma,mu=0,r=0,time=1,n)
{
value=(S)
......
tree = matrix(rev(tree), byrow = FALSE, ncol = n + 1)
... where did tree first get defined?
return(value[1])
... do you really want to return only value[1] _and_not_ tree? If
you exit the function this way, tree will get lost.
}
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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