Does this help. Shows how to use the basic functions to get at the answer:
> # add first day of month to make it valid > x <- as.POSIXct(paste('1', 'sep2009', sep=''), format="%d%b%Y") > # now advance one month and then go back one day for the end of the month > next.mon <- seq(x, length=2, by='1 month')[2] > last.day <- seq(next.mon, length=2, by='-1 day')[2] > last.day [1] "2009-09-30 GMT" > On Sun, Sep 13, 2009 at 2:18 PM, megh <megh700...@yahoo.com> wrote: > > Is there any R function to calculate automatically the last day of a > particular month? For example "sep2009" should be converted to last day of > September of 2009? > > Thanks > -- > View this message in context: > http://www.nabble.com/How-to-get-last-day-of-a-month--tp25425645p25425645.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.