Dear All,
I created a list (of length Z) in the following way:
my.array <- vector("list", Z)
then i assigned a matrix (of T rows by N columns) in each of the elements of
the list my.array in the following way:
my.array[[i]] <- matrix.data ##( matrix.data has dimensions TxN, and i
repeated this command for i from 1 to Z, the matrix.data contains only
numeric data)
and
1. i would like to extract all the third columns of each of the Z matrices
stored in my.array (such that i get a new list only with the 3rd columns of
each matrix in the elements of a new list)
2. i would like to know how could i replace all the 3rd columns of each
matrix in my.array if i have a second matrix (size ZxT) with these columns.
is there a simple way to do these tasks? i appreciate any hints or advice.
Carlos
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
