Try this:
dat <- read.table(textConnection("Timestamp1 Timestamp2
05:24:43 05:25:05
15:47:02 15:47:22
18:36:05 18:36:24
15:21:24 15:22:04"), T)
closeAllConnections()
Reduce("-", lapply(dat, strptime, format = "%H:%M:%S"))
On Wed, Sep 2, 2009 at 8:50 PM, sugo <iey...@sugimoto.at> wrote:
>
> Hi all,
>
> I have the following problem: I have a csv-file consisting of timestamp
> values (no dates), e.g.:
> Timestamp1;Timestamp2;
> 05:24:43;05:25:05;
> 15:47:02;15:47:22;
> 18:36:05;18:36:24;
> 15:21:24;15:22:04;
>
> I need a vector with the difference of the two timestamps, so I read the
> data with the read.csv-function:
> myObj <- read.csv("file.csv",header=TRUE,sep=";").
>
> I have then tried unsuccessfully to convert the data to time format (e.g.
> using the strptime function like date1 <-
> strptime(myObj[0],format="%H:%M:%S")) to be able to perform a datediff
> operation.
>
> I would be very grateful if anybody could give me some assistance.
>
> Thanks in advance,
> Ieyasu
> --
> View this message in context:
> http://www.nabble.com/diff-of-two-timestamps-tp25267603p25267603.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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