Greetings. I somehow had the impression that an infinite number, as obtained
by dividing by zero, for instance, would be flagged as both missing ("NA") and
not a number ("NaN"). It appears that I was wrong on both counts, although the
is.finite function correctly returns FALSE in such a case. Please see the
appended for some details. I guess that the bottom line is that R works the
way it works, but if you can add anything that will further instruct me, I'd
appreciate it.
Thanks.
-- Mike
> y <- 2/0
> y
[1] Inf
> is.na(y)
[1] FALSE
> is.nan(y)
[1] FALSE
> is.finite(y)
[1] FALSE
> z <- log(-1)
Warning message:
In log(-1) : NaNs produced
> z
[1] NaN
> is.nan(z)
[1] TRUE
> is.na(z)
[1] TRUE
-----
R version 2.9.2 (2009-08-24)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
-----
$ uname -a
Linux xxxxxxx.localdomain 2.6.29.6-217.2.16.fc11.x86_64 #1 SMP Mon Aug 24
17:17:40 EDT 2009 x86_64 x86_64 x86_64 GNU/Linux
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
