I highly suggest to rethink your problem in a way that you store the things labelled, e.g., TA1 to TA5 (as well as all the others) as the elements of a list TA. This way you have just one object TA that can easily be accessed by index operations and the code looks much cleaner in the end.

Best,
Uwe Ligges


Steven Kang wrote:
Dear R users,

I am trying to fill in arrays (5 different according to distinct "id")
from objects produced from arbitrary data set below.

  a <-
data.frame(id=rep(c("idA1","idA2","idA3","idA4","idA5"),2),pro=c("bb","uu","ee","tt","uu","gg","tt","bb","gg","ee"),sal=rpois(10,2))

      id    pro sal
1  idA1  bb   2
2  idA2  uu   0
3  idA3  ee   3
4  idA4  tt   2
5  idA5  uu   4
6  idA1  gg   3
7  idA2  tt   0
8  idA3  bb   1
9  idA4  gg   0
10 idA5  ee   5
My desired outputs (5 arrays/lists classified according to distinct "id"
field) are as follow:

TA1
bb ee gg tt uu
 2  0  3  0  0

TA2
bb ee gg tt uu
 0  0  0  0  0

TA3
bb ee gg tt uu
 1  3  0  0  0

...... similarly for TA4 & TA5.

The above results were produced using TA1 <-
c(bb=TA1.bb,ee=TA1.ee,gg=TA1.gg,tt=TA1.tt,uu=TA1.uu), TA2 <-
c(bb=TA2.bb,ee=TA2.ee,gg=TA2.gg,tt=TA2.tt,uu=TA2.uu*)* etc for TA3~TA5.
Although these generate the output I desire, I would like to use a single
statement for producing 5 different arrays (instead of 5 different
statements)

I have tried the following codes, however the last statement (paste("T",
substring(i,3,4), sep="") <- c(bb ......) gives error message reading "Error
in paste("T", substring(i, 3, 4), sep = "") <- c(bb = paste(paste("T",
: target of assignment expands to non-language object"

for (i in unique(a$id))
  for (j in unique(a$pro))
    assign(paste(paste("T", substring(i,3,4), sep=""), j, sep="."),
sum(subset(a, a$id == i & a$pro == j)$sal))
    paste("T", substring(i,3,4), sep="") <- c(bb=paste(paste("T",
substring(i,3,4), sep=""),j, sep="."),ee=paste(paste("T", substring(i,3,4),
sep=""),j, sep="."),

gg=paste(paste("T", substring(i,3,4), sep=""),j,
sep="."),tt=paste(paste("T", substring(i,3,4), sep=""),j, sep="."),

uu=paste(paste("T",
substring(i,3,4), sep=""),j, sep="."))

Your solution to this problem would be highly appreciated.



Steve

        [[alternative HTML version deleted]]

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to