Its not being stored as an integer. Its being stored as a double. If it were stored as an integer you would not get the e:
> as.character(1000000000L) [1] "1000000000" > as.character(as.integer(1000000000)) [1] "1000000000" On Sat, Aug 22, 2009 at 7:13 PM, Dajiang J. Liu<dajiang....@gmail.com> wrote: > Dear all,I want to convert a long integer to a string, and for example, > 100000000 > I used as.character(1000000000) e.g, and it gives me back 1e+???. What I > want is a exact form, not exponential form. Any ideas how to do it? Thank > you very much. > Regards, > Dajiang > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
