Just be aware that this only works if 'x' contains a single entry. If
'x' is a vector of multiple such entries, you will only get the
leading numbers in the first entry:
x2 <- c(x, x)
> x2
[1] "1041281__2009_08_20_.lev" "1041281__2009_08_20_.lev"
> strsplit(x2, split="_")[[1]][1]
[1] "1041281"
as compared to:
> sapply(strsplit(x2, split = "_"), "[", 1)
[1] "1041281" "1041281"
HTH,
Marc Schwartz
On Aug 21, 2009, at 3:08 PM, Stephan Kolassa wrote:
strsplit("1041281__2009_08_20_.lev", split="_")[[1]][1]
HTH,
Stephan
stephen sefick schrieb:
x <- "1041281__2009_08_20_.lev"
I would like to split this string up and only extract the leading
numbers.
1041281
to use as a label for a data column in a bigger for loop function to
read in data.
regards,
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