I have columns in two tables that need to be compared in order to get a statistic. The function calculating the statistic is somers2. Here are the two columns I must calculate, row by row.
name1 name2 1 Pred_pres_a_indpdt[,3,,] population[,23] 2 Pred_pres_b_indpdt[,3,,] population[,24] 3 Pred_pres_c_indpdt[,3,,] population[,25] 4 Pred_pres_d_indpdt[,3,,] population[,26] 5 Pred_pres_e_indpdt[,3,,] population[,27] 6 Pred_pres_f_indpdt[,3,,] population[,28] 7 Pred_pres_a_indpdt[,4,,] population[,23] 8 Pred_pres_b_indpdt[,4,,] population[,24] 9 Pred_pres_c_indpdt[,4,,] population[,25] 10 Pred_pres_d_indpdt[,4,,] population[,26] 11 Pred_pres_e_indpdt[,4,,] population[,27] 12 Pred_pres_f_indpdt[,4,,] population[,28] 13 Pred_pres_a_indpdt[,5,,] population[,23] 14 Pred_pres_b_indpdt[,5,,] population[,24] 15 Pred_pres_c_indpdt[,5,,] population[,25] 16 Pred_pres_d_indpdt[,5,,] population[,26] 17 Pred_pres_e_indpdt[,5,,] population[,27] 18 Pred_pres_f_indpdt[,5,,] population[,28] 19 Pred_pres_a_indpdt[,8,,] population[,23] 20 Pred_pres_b_indpdt[,8,,] population[,24] 21 Pred_pres_c_indpdt[,8,,] population[,25] 22 Pred_pres_d_indpdt[,8,,] population[,26] 23 Pred_pres_e_indpdt[,8,,] population[,27] 24 Pred_pres_f_indpdt[,8,,] population[,28] the somers2 function works like this: somers2(x, y) for example: somers2(Pred_pres_a_indpdt[,3,,], population[,23]) so somers2 is calculated for each row, with column 1 as x, column 2 as y. Is there anyway to automate this? -R -- View this message in context: http://www.nabble.com/automation-question-tp24761918p24761918.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.