On Mon, Jul 13, 2009 at 11:31 AM, Tom Liptrot <tomlipt...@hotmail.com> wrote:
> I wish to combine these two into one matrix using the values from x where x > has values, and values from a where x has NA's, giving a new matrix which > would look like this: This should do the trick: x[which(is.na(x))]=a[which(is.na(x))] -- Michael Knudsen micknud...@gmail.com http://www.google.com/profiles/micknudsen ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.