Hi Rolf,
My apologies for the inconvenience caused due to my reply @ "R-help diges".
Thanks for providing me a clue to solve the problem .
I modify a bit to populate a list. This is throwing an error
##### Error in `*tmp*`[[j]] : subscript out of bounds"
myData <- read.table("table.data",
header=T,
sep="\t",
comment.char = "#"
);
inp <- scan("table.data", what=list(comp=" ", A="", B="", C=""));
n <- c(0:length(inp$comp));
myList=list();
for(i in n-1)
{
if(i < length(inp$comp))
{
j=i+1;
myList[[j]][1] <-c(as.numeric(myData$A[i]));
myList[[j]][2] <-c(as.numeric(myData$B[i]));
myList[[j]][2] <-c(as.numeric(myData$C[i]));
}
}
print(myList);
Any idea where i'm doing a mistake which is causing this error.
Thanks in advance.
regards
Gaurav Kumar
--- On Fri, 10/7/09, Rolf Turner <r.tur...@auckland.ac.nz> wrote:
From: Rolf Turner <r.tur...@auckland.ac.nz>
Subject: Re: [R] How to Populate List
To: "gau...@gauravkumar.org" <gau...@gauravkumar.org>
Cc: "r-help@r-project.org" <r-help@r-project.org>
Date: Friday, 10 July, 2009, 1:39 AM
On 10/07/2009, at 2:55 AM, Gaurav Kumar wrote:
> Hi,
>
> I'm new to R and would like to know, how one can populate the list with array
> data.
> I'm reading a tab separated table in R. The data in the table looks something
> like this.
>
> #Table Data
> Comp A B C
> Extracellular 103 268 535759
> Nucleus 45603 47783 442744
>
> #R code
> myData <- read.table("table.data",
> header=T,
> sep="\t",
> comment.char = "#"
> );
> inp <- scan("table.data", what=list(comp=" ", A="", B="", C=""));
> n <- c(0:length(inp$comp));
> myList=list();
> for(i in n-1)
> {
> obj
><-c(as.numeric(myData$A[i]),as.numeric(myData$B[i]),as.numeric(myData$C[i]));
>
> }
>
> Need help to know if there is any function in R to push obj to myList
(a) You apparently ``replied'' to an R-help digest, and included megabytes
of totally irrelevant material in your post. It took me several minutes to
delete it.
STEP ONE: LEARN HOW TO USE EMAIL!!!
(b) Do the following:
myList <- list();
for(i in n-1)
{
myList[[i]]
<-c(as.numeric(myData$A[i]),as.numeric(myData$B[i]),as.numeric(myData$C[i]));
}
cheers,
Rolf Turner
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