how about sum(!is.na(x)) ?
On Tue, Jul 7, 2009 at 2:56 PM, Godmar Back<god...@gmail.com> wrote:
> Hi,
>
> is there a simpler way to count the number of elements in a vector
> that are not NA than this:
>
> countN <- function (v) {
> return (Reduce(function (x, y) x + y, ifelse(is.na(v), 0, 1)))
> }
>
> ?
>
> - Godmar
>
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