On Tue, Jul 7, 2009 at 12:20 PM, David Winsemius<dwinsem...@comcast.net> wrote:
> It looks like you are printing a matrix and that you want to print all rows
> of the first column before all rows of the second column. Apply should do
> it. Assume the matrix is named "AA"
>
> apply(AA, c(2,1), cat, "\n") # the \n is the line-feed character
>
I thought along these lines, too, but:
> AA
[,1] [,2] [,3]
[1,] "overallimpression" "yourinitialimpression" "managementprocess_as_ord"
[2,] 0.7440637 0.7270246 0.5550202
[,4]
[1,] "userinterfacechangedisplayorder:It was very easy to use with
either option"
[2,] -0.4476622
[ remainder deleted ]
> apply(AA, c(2,1), cat, "\n")
Error in cat(list(...), file, sep, fill, labels, append) :
argument 1 (type 'list') cannot be handled by 'cat'
This may give more information about what AA is:
> attributes(AA)
$dim
[1] 2 13
> is.matrix(AA)
[1] TRUE
- Godmar
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
