Dear Barry,
Thank you for the suggestion, it does work. I think the documentation
might be improved, but it's probably not a good idea to submit bug
reports just because I misunderstand what R does.
Best regards,
Craig
Barry Rowlingson wrote:
On Tue, Jun 30, 2009 at 1:00 PM, Craig P. Pyrame<crap...@gmail.com> wrote:
But this fails, as above. Why? Why can c(character, character) create a
list of two functions, but rep(character, 2) can't?
Another solution to my problem I could find (and you'll hopefully suggest an
even better one) is to use class names instead, like so:
types = lapply(c(rep('character', 2), 'integer', 'numeric', ...),
function(type) vector(type, 0))
but I am still curious why the above doesn't work as I would expect it to.
I hope this doesn't turn into a debate about expectations vs what
actually happens :)
I've discovered that rep(list(f),n) might do what you want:
> f=function(x){x*2}
> l=rep(list(f),5)
> l[[1]](4)
[1] 8
help(rep) says "It is a generic function" which translates to "you
may have some problem finding out exactly what function is called when
you do rep(thing)". I don't think there's a method for functions, so
it's probably being passed to the generic method which is expecting
vectors. It possibly then tries to get an element of f, and fails, a
bit like this:
> f[1]
Error in f[1] : object of type 'closure' is not subsettable
- without first checking if the object is a vector (you can do
rep(c(1,2),5) you see). Maybe a bug, or a misleading error message, or
a documentation problem: check with the latest version of R etc etc
etc read the FAQ before submitting a bug etc etc etc.
Barry
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