peng chen wrote:
Hi, R experts:
I am trying to generate data output in the following format:
rom_array := (
"00000000000000000000000000000000",
"00000000010010010110111111101100",
"00000000100100101101000001011111",
"00000000110111000001000111100011",
"00000001001001010010010100001001",
"00000001011011011111101001101001")
I have all the necessary data line, however, I am having trouble generating
the double quotation marks along with the trailing comma for each line.
Hi Peng and others,
I assumed that you wanted to generate that (Pascal?) expression and you
have a character or binary numeric vector of the six elements. Say that
vector is named "binaryvector".
cat("rom_array := (\n")
ends<-c(rep("\",\n",5),"\")\n")
for(i in 1:length(binaryvector))
cat("\"",binaryvector[i],ends[i],sep="")
should do what you want. However, I have two questions:
1) Why does cat put a newline at the end of a call with a sep argument
with a newline in it? It doesn't put the sep argument after the last
element of the vector, even though the help page says that it does.
2) The help page reads:
sep a character vector of strings to append after each element.
but cat clearly uses only the first string of the vector. Am I reading
this wrongly?
Jim
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
